# Python Zipapp Module

The `zipapp` module provides tools to manage the creation of zip files containing Python code, which can be executed directly by the Python interpreter. The module provides both a Command-Line Interface and a Python API.

## Importing the Module

```python
import zipapp
```

## Command Line Usage

You can create an executable archive from a directory containing Python code.

```bash
# Create an archive 'myapp.pyz' from the directory 'myapp'
python -m zipapp myapp
```

You can specify the main function to run using `-m`.

```bash
python -m zipapp myapp -m "myapp:main"
```

You can also specify the interpreter shebang using `-p`.

```bash
python -m zipapp myapp -p "/usr/bin/env python3"
```

## Programmatic Usage

### `zipapp.create_archive()`

Create an application archive from `source`, which can be a directory name or a file-like object.

```python
import zipapp

# Create an archive from a directory
zipapp.create_archive('myapp', 'myapp.pyz')
```

### Specifying Main and Interpreter

You can specify the entry point and the interpreter.

```python
import zipapp

zipapp.create_archive(
    'myapp', 
    'myapp.pyz', 
    interpreter='/usr/bin/env python3', 
    main='myapp:main'
)
```

### `zipapp.get_interpreter()`

Return the interpreter specified in the `#!` line at the beginning of the archive.

```python
import zipapp

interpreter = zipapp.get_interpreter('myapp.pyz')
print(interpreter)
```

[[programming/python/python]]